Mathematics, 31.08.2019 17:00, dragonmaster837
Find f'(0.3) for f(x)= the integral from 0 to x of arccos(t)dt
Answers: 1
![\bf \textit{using the 2nd fundamental theorem of calculus}\\\\ \cfrac{dy}{dx}\displaystyle \left[ \int\limits_{0}^{x}\ cos^{-1}(t)dt \right]\implies cos^{-1}(x) \\\\\\ f'(0.3)\iff cos^{-1}(0.3)\approx 1.26610367277949911126](/tpl/images/0215/4543/c0040.png)
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