Mathematics, 28.01.2020 06:31, jholland03
Prove that w^49+w^101+w^150=0,where w is a complex cube root of unity
Answers: 2
is a cube root of unity, you have 
. So
. Any other cube root of unity will make the numerator vanish, so the equality holds.
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Prove that w^49+w^101+w^150=0,where w is a complex cube root of unity...
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