Arectangle has a perimeter of 30 feet and an area of 50 square feet. what are the dimensions of the rectangle?

Perimeter of rectangle = 2L + 2W
Area = L x W
L x W = 50
2L + 2W = 30
There's a quick way to determine this. Find the factors of 50 as a product.
2 x 25, 5 x 10.
We can use these factors as sides (dimensions).
2x2 + 2x25 = 4 + 50 = 54, incorrect factors.
2x5 + 2x10 = 10 + 20 = 30, correct.
Your dimensions are 5 and 10.

 5 ft x 10 ft. 

(2) 5ft  + (2) 10ft  = 30 ft. 

5 x 10 = 50 sq ft

The question is kind of confusing. if it's asking how many variations of answers can you give. then do 4^5 for your answer.this would be something like the first question could be a and the 2nd c or first b next c etc. if you can, ask the teacher for a better confirmation of what it's asking. if i'm assuming correctly what it's asking, it's 625 different variations.