Solve the system of equations algebraically. show all your steps.

y = x^2 + 2x

y = 3x + 20

Given the system of equation:

           .....[1]

             .....[2]

equate these two equations we have;

Subtract 3x from both sides we have;

We can write this as:

⇒

⇒

⇒

By zero product property we have;

x-5 = 0 and x+4 = 0

⇒x = 5 and x = -4

Substitute these in [2] we have;

For x =5

(5, 35)

For x = - 4

(-4, 8)

Therefore, the solutions for the given system of equations are: (5, 35) and (-4, 8)