Abag contains two steel balls and five brass balls. the total weight of the bag is 13 pounds. if two steel balls are added and two brass balls are removed, the bag’s weight decreases to 12 pounds. if s is the weight of a steel ball and b is the weight of a brass ball, the system of linear equations representing this situation is? solving the system of linear equations, the weight of a steel ball is ? and the weight of a brass ball is?

The linear equations are 2s + 5b = 13 , 4s + 3b = 12 and the weight of a steel ball is 1.5 pound , the weight of the brass ball is 2 pound .

Step-by-step explanation:

As

s is the weight of a steel ball and b is the weight of a brass ball.

As given

A bag contains two steel balls and five brass balls.

The total weight of the bag is 13 pounds.

Equation becomes

2s + 5b = 13

As given

If two steel balls are added and two brass balls are removed, the bag’s weight decreases to 12 pounds.

4s + 3b = 12

Thus linear equation becomes

2s + 5b = 13

4s + 3b = 12

Thus multiply 2s + 5b = 13 by 2 and subtracted from 4s + 3b = 12 .

4s - 4s + 3b - 10b = 12 - 26

-7b = -14

b = 2 pound

Put the value of b in the equation 2s + 5b = 13 .

2s + 5 × 2 = 13

2s + 10 = 13

2s = 13 - 10

2s = 3

s = 1.5 pound

Therefore the linear equations are 2s + 5b = 13 , 4s + 3b = 12 and the weight of a steel ball is 1.5 pound , the weight of the brass ball is 2 pound .

it will cost dollar $540

the living room is 3 which means if we divide 325/3 then we get $108

therefore if 1part of the living room cost $108 and 3 costed $325

then total 5part of the room will cost 5*108 which gives $540

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step-by-step explanation:

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