Write the function in vertex form.
y=4x2 - 8x + 5

a=4, b=-8, c=5

h=-b/2a= -(-8)/2(4)

8/8=h=1

K= a(h)^2+b(h)+c

K= 4(1)^2-8(1)+5

K= 4-8+5

K= 1, Vertex  Form: a(x-h)^2+k

Vertex Form: Y= 4(X-(1)^2+K

Y= 4(x-1)^2+1

given that triangle abc is transformed two times to get triangle

a"b"c"

first abc is transformed in to a'b'c' as follows:

the coordinates of a are (1,-1) and transformed into a'(-1,1)

similarly b (4,-2) became b'(-4,2) and

c(7,-2) became c'(-7,2)

i.e. (x,y) becomes (-x,-y)

this is nothing but reflection about a point here origin.

thus first transformation is reflection on the origin.

next is exactly shifting 3 units down

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