Mathematics, 09.10.2019 11:30, Squara

Is easy 878+914 then i think i should cheak it my self

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answered: Guest

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option

What are the zeros of the function f(x)=x^3-2x^2-3x !

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Is easy 878+914 then i think i should cheak it my self...