Mathematics, 28.12.2019 19:31, arthurdolz
Solve for x: 2 over quantity x minus 2 plus 7 over quantity x squared minus 4 equals 5 over x.
x = negative 4 over 3 and x = −5
x = negative 4 over 3 and x = 5
x = 4 over 3 and x = −5
x = 4 over 3 and x = 5
Answers: 3
![[x(x^{2} -4)]](/tpl/images/0435/9765/9f399.png)
both sides![[x(x^{2} -4)]\frac{2}{x-2}+[x(x^{2} -4)]\frac{7}{x^{2}-4}= [x(x^{2} -4)]\frac{5}{x}](/tpl/images/0435/9765/8cee3.png)
is equal to
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Solve for x: 2 over quantity x minus 2 plus 7 over quantity x squared minus 4 equals 5 over x.
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