Mathematics, 06.10.2019 19:00, evelin23
If the quadratic formula is used to find the roots of the equation x^2-6x-19=0, what is the correct roots
Answers: 3
![x^{2} -6x-19=0 \\ \\discriminant= b^{2}-4ac= \\ 36-(-76)=76+36=112 \\ \\ -b- \sqrt{disc.}/2a=6- \sqrt{112}/2 \\ =6- 4\sqrt{7}/2 \\ =3- 2\sqrt{7} \\ \\ -b +\sqrt{disc}/2a=6+4 \sqrt{7} /2 \\ =3+ 2\sqrt{7} \\ \\ Solution\: set:(3- 2\sqrt{7} ,3+ 2\sqrt{7} ) \\ \\ \framebox[1.1\width]{Good Luck!!} \par](/tpl/images/0294/6434/747a6.png)
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If the quadratic formula is used to find the roots of the equation x^2-6x-19=0, what is the correct...
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