For a > b > c 0 and a + b + c = 1,
show that

Starting with what we know:
is the same as:



Now, let's use our inequality and bring it into our equation.
Since a > b and b >0, then a > 0
Thus, we can multiply both sides by a, b, or c since they are all positive values.

We can say: , since b > 0
Similarly, and

Now, we've got values for ab, ac, and bc.
Using this information back into our original equation:


Since , then we can say:
and
as required.

Hmm i believe it would be c