Three consecutive odd integers have a sum of 33.

I don't know if I understood the question correctly, but you said 3 odd consecutive numbers so I'd say 11+11+11=33

Or since they are consecutive numbers it could also be 10+11+12=33 
(but I know 10 and 12 are not odd)

Let your three integers be x - 2, x, and x + 2, provided x is an odd number.

Now, x - 2 + x + x + 2 = 33
3x = 33
Thus, x = 11

Now, since x = 11, your remaining two numbers are 9, and 13.
And 9 + 11 + 13 = 33
So, your three numbers are 9, 11, and 13.

17 or maybe it’s about 2