Sanjay begins to correctly graph the function f(x) = (x + 1)2 – 3. based on the axis of symmetry and the vertex, which graph could be sanjay’s?

see the attached figure to better understand the problem

we have

this is a quadratic equation (vertical parabola) open up

the vertex is a minimum

the vertex is the >

we know that

the axis of symmetry in this case is the x-coordinate of the vertex

so

the axis of symmetry is

therefore

the answer is the option c

F(x) = (x+1)² - 3

graph a - incorrect
x = 1
f(1) = (1+1)² - 3
f(1) = 2² - 3
f(1) = 4 -3 
f(1) = 1
(1,1)

graph b - 
x = -3
f(-3) = (-3+1)² - 3
f(-3) = -2² - 3
f(-3) = 4-3
f(-3) = 1
(-3,1)

graph c
x = -1
f(-1) = (-1+1)² - 3
f(-1) = 0² - 3
f(-1) = -3
(-1,-3)

graph d - incorrect
x = 3
f(3) = (3+1)² - 3
f(3) = 4² - 3
f(3) = 16 - 3
f(3) = 13
(3,13)

either b or c can be sanjay's because they were graphed correctly.

You have to give us options