1. what is the slope of the line through the points (-2, 4) and (-1, -1)
2. what is the slope of the line for the equation x = 3
3. identify the x and y intercepts for the equation 4x - 3y = -12
4. write the equation of the line given the slope and a point on the line. type your answer in the box without skipping any spaces. m = 3, point (5, 10)

if the eqn of the parabola is f(x) = (x-4)(x+2), we need to mult. this out to find the coordinates of the vertex.

then f(x) = x^2 + 2x - 4x - 8, and f(x) = x^2 - 2x - 8.

one way in which you can find the vertex is to calculate x = -b / (2a).   here, that comes to

        )

x = = 1.   f(1) = 1^2 - 2(1) - 8 = - 9.   vertex is at (1, -9).

        2(1) 

find another point on the curve:   let x=0, for which y=-8.   then (0, -8) is on the curve.   plot the vertex and this point and draw a smooth parabola thru both.

hope this

answer: options?

step-by-step explanation: