Mathematics, 29.12.2019 08:31, cyaransteenberg

Leonard spent 1/4 of his money on a sandwich. he spent 2times as much on a gift for his brother as on some comic books. he had 3/8 of his money left. what fraction of his money did he spend on the comic books

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answered: cuhh

Leonard spend $\displaystyle \frac{1}{8}$ of his money on the comic books

Further explanation

Fraction numbers are known as numerator and denominator

On a number line, fractions are expressed in points that lie between two integers

The general form of fractions is

$\large{\boxed{\bold{\frac{a}{b}} }$

a = numerator

b = denominator

Mixed fractions consist of whole number and ordinary fractions

Let M = All Leonard money

Leonard spent 1/4 of his money on a sandwich.

we translate this sentence into equation

$\displaystyle S=\frac{1}{4} M$

He spent 2 times as much on a gift for his brother as on some comic books.

a gift = 2 x comic books

let x = comic books

so a gift = 2x

we translate this sentence into equation

$\displaystyle G=2\:CB$

$\displaystyle \frac{3}{8}$ of his money left

So the total money:

= sandwich money + gift + comic books + the rest of money

= $\frac{1}{4}+2x+x+\frac{3}{8}=\frac{8}{8}$

= $\displaystyle \frac{1}{4}+\frac{3}{8}+3x=\frac{8}{8}$

= $\displaystyle \frac{2}{8}+\frac{3}{8}+3x=\frac{8}{8}$

= $\displaystyle \frac{5}{8}+3x=\frac{8}{8}$

= $\displaystyle 3x=\frac{8}{8}-\frac{5}{8}$

= $\displaystyle 3x=\frac{3}{8}$

= $\displaystyle x=\frac{3}{24}=\frac{1}{8}$

so x = money for comic books = $\displaystyle \frac{1}{8}$

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Keywords: fraction, money, comic books

Leonard spent 1/4 of his money on a sandwich. he spent 2times as much on a gift for his brother as o

answered: Guest

Answer d; a supplementary angle = 180°, so if that angle = 150°, y would = 30°.
In the diagram below, ab is parallel to cd. what is the value y? a.150b.50c.60d.30

answered: Guest

when functions are first introduced, you will probably have some simplistic "functions" and relations to deal with, usually being just sets of points. these won't be terribly useful or interesting functions and relations, but your text wants you to get the idea of what the domain and range of a function are. small sets of points are generally the simplest sorts of relations, so your book starts with those.

step-by-step explanation:

state the domain and range of the following relation. is the relation a function?

{(2, –3), (4, 6), (3, –1), (6, 6), (2, 3)}

the above list of points, being a relationship between certain x's and certain y's, is a relation. the domain is all the x-values, and the range is all the y-values. to give the domain and the range, i just list the values without duplication:

domain: {2, 3, 4, 6}

range: {–3, –1, 3, 6}

(it is customary to list these values in numerical order, but it is not required. sets are called "unordered lists", so you can list the numbers in any order you feel like. just don't duplicate: technically, repetitions are okay in sets, but most instructors would count off for this.)

while the given set does indeed represent a relation (because x's and y's are being related to each other), the set they gave me contains two points with the same x-value: (2, –3) and (2, 3). since x = 2 gives me two possible destinations (that is, two possible y-values), then this relation is not a function.

note that all i had to do to check whether the relation was a function was to look for duplicate x-values. if you find any duplicate x-values, then the different y-values mean that you do not have a function. remember: for a relation to be a function, each x-value has to go to one, and only one, y-value.

state the domain and range of the following relation. is the relation a function?

{(–3, 5), (–2, 5), (–1, 5), (0, 5), (1, 5), (2, 5)}

i'll just list the x-values for the domain and the y-values for the range: