Which of the following dimensions form a trapezoid with an area of 4 1/8 square units?
a- h= 1 1/2, b1 = 6, b2 = 3 1/2
b- h=1 1/2, b1 = 2, b2 = 3 1/2
c- h= 3, b1 = 2, b2 = 3 1/2
d- h= 1 1/2, b1 = 2, b2 = 7

The area of a trapezoid is  (¹/₂) (height) (base-1 + base-2)

A). Area = (¹/₂) (1¹/₂) (6 + 3¹/₂) = (¹/₂) (³/₂) (¹⁹/₂) = ⁵⁷/₈ = 7¹/₈

B). Area = (¹/₂) (1¹/₂) (2 + 3¹/₂) = (¹/₂) (³/₂) (¹¹/₂) = ³³/₈ = 4¹/₈  <===

C). Area = (¹/₂) (3) (2 + 3¹/₂) = (¹/₂) (⁶/₂) (¹¹/₂) = ⁶⁶/₈ = 8¹/₄

D). Area = (¹/₂) (1¹/₂) (2 + 7) = (¹/₂) (³/₂) (¹⁸/₂) = ⁵⁴/₈ = 6³/₄

Hey mate here is the answerthe correct answer is b may it will you