Two movie tickets and 3 snacks are $25. three movie tickets and 4 snacks are $35. how much is a movie ticket and what is the average price of a snack. solve this equation by elimination

Let the tickets be x and the snacks be y.

2x + 3y = 25 equation(1) *3 => 6x+9y = 75... (3)

3x + 4y = 35 (2) *2 => 6x + 8y= 70(4)

on (3) - (4)

we get,
6x + 9y = 75
6x + 8y = 70
(-)  (-)      (-)

      y    =    5

on putting value of y in (1),
2x + 3*5 = 25

=>2x= 25-15 => 2x = 10 =>x= 10/2 => x= 5

hence , a movie ticket is $5 as well as a snack is $5

1195 was the store owner's profit.

In all honesty, there really is no “work” per say to show. mainly it’s just using the process of elimination. the question is asking which domain(s) would be the most appropriate for the function c(n). n is the number of observed vehicles so right away, 1, 2, and 3 can be eliminated.why? 1, 2 start in the negatives and therefore it is impossible to observe negative cars. so, #4 would be the best answer to the given problem.