Two urns contain white balls and yellow balls. the first urn contains 3 white balls and 6 yellow balls and the second urn contains 3 white balls and 8 yellow balls. a ball is drawn at random from each urn. what is the probability that both balls are white?

We have 3 white balls in the first urn out of 9. That means we have a 1 in 3 chance at picking the white ball in the first urn.

Now, we have a 3 in 11 chance at picking the white ball in the second urn.

Since, we want them simultaneously, we need to multiply them.

1/3 × 3/11 = 1/11 chance

The answer is c because you turn 17.5% into a decimal which gives you .175 then you times that by $361.35 which gives you 63.23625 but then you round that which gives you 63.24. then you at 63.24 pulse 361.35 and you round it which gives you $425