10 students will stand equidistant from the center of the classroom. they are all holding hands to begin with. they must go and shake hands with all other students whose hands they are not holding. no handshake will occur more than once. how many handshakes will take place?

The total number of handshakes that occur are:

                                   35

Step-by-step explanation:

Since, the total number of people are 10.

Also, the handshakes occur between the people who are not adjacent to each other.

Since, the formula that can be used to solve this is:

where represent the number of ways such that every 2 person shake hands and 10 is subtracted with the number of cases that are adjacent to each other i.e. the person standing adjacent do not shake hands.

Hence, on solving we get: 35

           There are a total of 35 handshakes.

d

step-by-step explanation:

given

y + 3 = - 4(x - 2) ← distribute the parenthesis

y + 3 = - 4x + 8 ( subtract 3 from both sides )

y = - 4x + 5 → d

idk

step-by-step explanation: i just don't