Daniel potter bought a new car for $20,000.00. two years later, he wanted to sell it. he was offered $14,650.00 for it. if he sold it for that amount, what was his depreciation rate?

Daniel sold the car for $14,650 ÷ $20,000 = 0.73, or 73% of its original value. Thus, the depreciation rate was 100% – 73% = 27%

= 27 %

this is a very good question

step-by-step explanation:

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step-by-step explanation:

the original amount doesn't ''re just looking for the time it takes for 1/2 of the substance to we have

(1/2) =)     take the ln   of both sides

ln (1/2)   = )   and we can write

ln(1/2) = ) lne     and lne   = 1     so we have

ln(1/2) = -.1092t     divide both sides by -.1092

t = ln(1/2)/-.1092 = about 6.347 days = about 6.3 days (rounded)