Mathematics, 30.08.2019 07:20, caschmitt3821

How do you work this out ? h= -16t²+64+0=0

Answers: 2

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Answers

Add 64 and 0
then add 16t^2 from =0
then you should have h= 16t^2=64
then take the square root of both 16t^2 and 64
then you should have 4t +- 8
that should give you your answer

answered: azaz1819

H = -16t² + 64 + 0
-16t² + 64 + 0
t = -64 +/- √(64² - 4(-16)(0))
   2(-16)
t = -64 +/- √(4096 + 0)
   -32
t = -64 +/- √4096
-32
t = -64 +/- 64
   -32
t = -64 + 64 t = -64 - 64
   -32    -32
t = 0 t = -128
   32    -32
t = 0 t = 4

h = -16t² + 64t + 0 h = -16t² + 64t + 0
h = -16(0)² + 64(0) + 0      h = -16(4)² + 64(4) + 0
h = 16(0) + 0 + 0    h = -16(16) + 256 + 0
h = 0 + 0 + 0     h = -256 + 256 + 0
h = 0 + 0    h = 0 + 0
h = 0    h = 0
(t, h) = (0, 0) (t, h) = (4, 0)

answered: Guest

pentagon

step-by-step explanation:

the coordinates a(5, -2), b(3,-1),c(-4,-4) d(-3,8) and e(-1,4) forms the vertices of the polygon when they are connected in order.

in order to classify that which polygon is it with the given coordinates, first count the number of vertices and then count the number of sides it can make with these vertices.

since, the given coordinates have five vertices, therefore, it will make five sides. moreover, pentagon is regular in nature therefore it will be convex.

now, a polygon with five sides is known as pentagon, therefore, the given polygon is the pentagon.

answered: Guest

find the magnitude of the trig term

csc

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by taking the absolute value of the coefficient.

find the lower bound of the range.

tap for more

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find the upper bound of the range.

tap for more

the range is

≤

−

≥

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−

∞

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∪

[

∞

)

{

≤

−

≥

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step-by-step explanation:

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