Ming needs 1/2 pint of red paint for an art project. he has 6 jars that have the following amounts of red paint in them. he wants to use only 1 jar of paint. mark all the jars of paints that ming can use. *there is more that 1 answer* a. 2/3 pint b.1/4 pint c.4/6 pint d.3/4 pint e. 3/8 pint f.2/6 pint

The jars that Ming can use are:

Jar A

Jar C

and Jar D

Ming needs 1/2 pint of red paint for an art project.

He has 6 jars that have the following amounts of red paint in them:

A. 2/3 pint

B. 1/4 pint

C. 4/6 pint

D. 3/4 pint

E.  3/8 pint

F. 2/6 pint

He wants to use only 1 jar of paint.

i.e. the jar which has less than 1/2 pint of paint can't be used.

A jar:

It has 2/3 pint of paint now we need to check whether this quantity is less than or grater than equal to 1/2.

We try to make the denominator same of both the quantities.

As:

2/3=4/6

Also 1/2=3/6

Since, 4/6> 3/6

hence A jar could be used.

B jar:

It has 1/4 pint of paint.

As 1/2=2/4

Also 1/4<2/4.

Hence Jar B can't be used.

C jar:

It has 4/6 pint of paint.

As 1/2=3/6

Now 4/6> 3/6

Hence jar C could be used.

D jar:

3/4 pint.

as 1/2=2/4

Hence, 3/4>2/4

Hence, jar D could be used.

E jar:

It has 3/8 pint of paint.

As 1/2=4/8

As 3/8<4/8

Hence jar E can't be used.

F jar:

It has 2/6 pint of paint.

As 1/2=3/6

Hence, 2/6<3/6

Hence, jar F can't be used.

3, 12, 48, 384, 1536, 6144, 24576, 98304

step-by-step explanation:

just keep timing it by 4.

your question is incomplete, write all the numbers in the sequence that it tells you.  

step-by-step explanation: