Solve this problem by using a two order system. a man invests $5,200, part at 4% and the balance at 3%. if his total income for the two investments is $194, how much money did he invest at each rate? $ a0 at 4% and $ a1 at 3%

Let $x be the amount of money that a man invested in 3% account and $y be the amount of money a man invested at 4% account. The problem can be modelled by the system of two equations.

1. The income for the 1st investment is $0.03x and the income for the 2nd investment is $0.04y.

If his total income for the two investments is $194, then

0.03x+0.04y=194.

2. If a man invests $5,200, part at 4% and the balance at 3%, then

x+y=5,200.

3. You get a system of equations:

From the 1st equation express x and substitute it into the 2nd equation:

Then

$1,400 at 3% and $3,800 at 4%.

6x = 48

i hope this . 6 cards each and a total of $48. dvide each side by 6 and you will have your answer.

the answer is 13/48

step-by-step explanation: