![\bf (x-5)^2+(x+3)^2=25\implies (x-5)^2+[x-(-3)]^2=5^2\\\\ -----------------------------\\\\ \textit{equation of a circle}\\\\ (x-{{ h}})^2+(y-{{ k}})^2={{ r}}^2 \qquad center\ ({{ h}},{{ k}})\qquad radius={{ r}}](/tpl/images/0273/8163/f03ba.png)
Identify the center and radius of a circle with equation (x-5)^2+(x+3)^2=25
a-center at...
Mathematics, 29.09.2019 13:10, jameskatzfeystu70
Identify the center and radius of a circle with equation (x-5)^2+(x+3)^2=25
a-center at (5,-3) ; radius : 25
b-center at (5,-3) ; radius : 5
c-center at (-5,3) : radius ; 25
d- center at (-5,3) radius : 5
Answers: 1
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