Four polynomial functions are shown below:

f(x) = x3 + 3x2 - 4x - 12
g(x) = x3 - 3x - 2
p(x) = x2 + 3x + 2
t(x) = x2 + x - 2
which of the following functions has 1 and -2 as its zeros?

f(x)
g(x)
p(x)
t(x)

Easiest way is to subsitute 1 for x and evaluate then -2 for x and evaluate
if they evaluate to 0 then they are roots

f(x)
if we did 1 for first one we get f(1)=-12 so 1 is not a zero

g(x)
if we did 1 for g(x) we get g(1)=-4, so 1 is not  a zero

p(x)
if we did 1 for p(x) we get p(1)=6 so 1 is not a zero

t(x)
if we did 1 for t(x) we get t(1)=0, so 1 is a zero
try -2
if we did -2 for t(x) we get t(-2)=0, so it is also a zero

t(x) is answer

What’s the equation you are trying to solve to get x?