![\bf \cfrac{sec(x)sin(x)+cos(\pi -x)}{1+sec(x)}\\\\ -----------------------------\\\\ sec(\theta)=\cfrac{1}{cos(\theta)}\qquad \qquad cos(\pi )=-1\qquad sin(\pi )=0 \\\\ cos({{ \alpha}} + {{ \beta}})= cos({{ \alpha}})cos({{ \beta}})- sin({{ \alpha}})sin({{ \beta}})\\\\ -----------------------------\\\\ \cfrac{\frac{1}{cos(x)}sin(x)+[cos(\pi )cos(x)+sin(\pi )sin(x)]}{1+\frac{1}{cos(x)}} \\\\\\ \cfrac{\frac{sin(x)}{cos(x)}+[-1\cdot cos(x)+0\cdot sin(x)]}{\frac{cos(x)+1}{cos(x)}}](/tpl/images/0464/4726/9f39a.png)
![\bf \cfrac{\frac{sin(x)}{cos(x)}+[-cos(x)]}{\frac{cos(x)+1}{cos(x)}}\implies \cfrac{\frac{sin(x)-cos^2(x)}{cos(x)}}{\frac{cos(x)+1}{cos(x)}} \\\\\\ \cfrac{sin(x)-cos^2(x)}{cos(x)}\cdot \cfrac{cos(x)}{cos(x)+1}\implies \cfrac{sin(x)-cos^2(x)}{cos(x)+1}](/tpl/images/0464/4726/0669b.png)
How do you simplify the following trigonometric expression:
(...
Mathematics, 21.01.2020 20:31, rakanmadi87
How do you simplify the following trigonometric expression:
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