What is the vertex of this equation?
y=-x^2+10x-21

(5, 4)

(1, -9)

(-4, -2)

(7, -3)

  (5, 4)

Step-by-step explanation:

The equation can be written in vertex form by adding and subtracting 25:

  y = -(x^2 -10x +25) -21 +25

  y = -(x -5)^2 +4

Then the vertex can be identified as (5, 4).

answer with step-by-step explanation:

a. ∠j is supplementary to ∠k - true:

(opposite angles of a trapezoid are supplementary which means that they add up to 180 degrees)

b. kl is parallel to jm - true:

(opposite sides are parallel to each other in a trapezoid)

c. jk is perpendicular to kl - false:

(clearly, jk does not make a right angle with kl)

d. jk is parallel to lm - false:

(jk and lm are two lines opposite in direction to each other so they cannot be parallel)

e. ∠j is congruent to ∠m - true:

(the angles on each side of the base are congruent)

f. ∠j is congruent to ∠k - false:

(the angles on the same side but opposite side of the base are not congruent)

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