Which of the following sets shows all the numbers from the set {1, 2.5, 3, 4.5, 5} that make the inequality 3a + 4 ≥ 13 true?
a; {2.5, 3, 4.5}
b; {1, 2.5}
c; {3, 4.5, 5}
d; {4.5, 5}

The correct Options are : C; {3, 4.5, 5}

Step-by-step explanation:

3a + 4 ≥ 13

Subtracting 4 from both the sides

⇒ 3a + 4 - 4 ≥ 13 - 4

⇒ 3a ≥ 9

Dividing by 3 both the sides

⇒ a ≥ 3

Therefore, The numbers from the set are : 3 , 4.5 , 5

Thus, The correct Options are : C; {3, 4.5, 5}

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)