How do you graph y-2x=0 and y=6x - 10

The first step before graphing these is to ensure they are both in y=mx+b (slope-intercept) format.
Only the first one (y-2x=0) is not.
To convert this to slope-intercept form, just add 2x to both sides so y is isolated!
This leaves us with y=2x+0, which is in slope-intercept form.
When graphing these, you must identify the slope and the y-intercept.
In y=mx+b form, the m is slope and b is y-intercept.
In y=2x+0, the slope is 2 and the y-intercept is 0.
This means there is a slope of positive 2 and the y-intercept is (0, 0).
The y-intercept is the y-value where ever x=0.
In y=6x-10, the slope is 6 and the y-intercept is -10.
This means there is a slope of positive 6 and the y-intercept is (0, -10).

Hope this helps! :)

I’m going to infer you said parallel.solve for yy= -1/2x+7/4lines that are parallel have the same slope, different y intercept.so we know m is -1/2then from there solve for y intercept.