Triangle abc is translated according to the rule (x, y) → (x + 2, y – 8). if the coordinates of the pre-image of point b are (4, –5), what are the coordinates of b'? (2, 3) (1, –9) (–3, –4) (6, –13)

the coordinates of B' is (6,-13)

Step-by-step explanation:

Triangle ABC is translated according to the rule (x, y) → (x + 2, y – 8).

Given :Coordinates of the pre-image of point B are (4, –5)

Apply the translated rule to get the coordinates of B'

rule (x, y) → (x + 2, y – 8)

Add 2 with x  and -8 with y to get the new coordinates

Point (4,-5) -> (4+2, -5-8) -> (6,-13)

So the coordinates of B' is (6,-13)

the coordinates of B' is (6,-13)

Step-by-step explanation:

Triangle ABC is translated according to the rule (x, y) → (x + 2, y – 8).

Given :Coordinates of the pre-image of point B are (4, –5)

Apply the translated rule to get the coordinates of B'

rule (x, y) → (x + 2, y – 8)

Add 2 with x  and -8 with y to get the new coordinates

Point (4,-5) -> (4+2, -5-8) -> (6,-13)

So the coordinates of B' is (6,-13)

.5 lb

step-by-step explanation:

12 in / 6 in =2 in

.25 x 2 = .5 lb

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180