Solve the system of equations
y=2x^2-3
y=3x-1

Any solution also mean y=y so

2x^2-3=3x-1

2x^2-3x-2=0

2x^2-4x+x-2=0

2x(x-2)+1(x-2)=0

(2x+1)(x-2)=0

So there are two solution for this system when x=-1/2 and x=2 to two solutions than are:  (use either original equation to solve for the corresponding y values..)

(-0.5, -2.5) and (2, 5)

Atranslation 6 units to the right and 4 down