This is josh's solution for the equation: x^2-6x-7=0
x^2-6x-7=0
x^2-6x=7
x^2-6x+9...
Mathematics, 28.08.2019 19:40, hamaama
This is josh's solution for the equation: x^2-6x-7=0
x^2-6x-7=0
x^2-6x=7
x^2-6x+9=7+9
(x-3)^2=16
x-3=16
x=19
x-3=-16
x=-13
is josh's solution correct? explain.
Answers: 2
Mathematics, 21.06.2019 17:00, landenDfisher
For the rule of 78, for a 12-month period, the last term in the sequence is 12 and the series sums to 78. for an 10 month period, the last term is and the series sum is . for a 15 month period, the last term is and the series sum is . for a 20 month period, the last term is and the series sum is
Answers: 2
Mathematics, 21.06.2019 22:10, ansonferns983
Given: ae ≅ ce ; de ≅ be prove: abcd is a parallelogram. we have that ab || dc. by a similar argument used to prove that △aeb ≅ △ced, we can show that △ ≅ △ceb by. so, ∠cad ≅ ∠ by cpctc. therefore, ad || bc by the converse of the theorem. since both pair of opposite sides are parallel, quadrilateral abcd is a parallelogram.
Answers: 1
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