ツy=-x^2-2. identify the vertex of the graph. tell whether it is a minimum or ツ

a.) (0, –2); minimum
b.) (–2, 0); minimum
c.) (0, –2); maximum
d.) (–2, 0); maximum

Hey!

Hope this Helps...

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Below, I added what the graph of (x^2)-2 looks like...

The answer is A. (0, -2); Minimum

the correct answer is option C because it is maximum at (0,-2)

Step-by-step explanation:

given equation,

y = -x² -2

to find maxima and minima we will differentiate the equation

hence we can see that double differentiation is - ve so the equation will maximum.

hence, now putting value from option C

the value of y comes out to be -2

now, putting value from option D

value of y comes out to be -6

hence, the correct answer is option C because it is maximum at (0,-2)

step-by-step explanation:

to find if any function is an inverse of the other, put the first equation in as x in the next one. then simplify and solve. if at the end you get the statement y = x, then it is an inverse. if you get anything else, it is not.

25/14 or 1.

step-by-step explanation:

the dots mean that it has infinitely more numbers behind it