Mathematics, 23.09.2019 15:30, asmaamasto
The volumes of two similar solids are 210 m3 and 1,680 m3. the surface area of the larger solid is 856 m2.
what is the surface area of the smaller solid?
Answers: 2
![\bf \qquad \qquad \textit{ratio relations} \\\\ \begin{array}{cccllll} &Sides&Area&Volume\\ &-----&-----&-----\\ \cfrac{\textit{similar shape}}{\textit{similar shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3} \end{array}\\\\\\\\ -----------------------------\\\\ \cfrac{\sqrt[3]{s^3}}{\sqrt[3]{s^3}}=\cfrac{\sqrt{s^2}}{\sqrt{s^2}}=\cfrac{s}{s}\implies \cfrac{\sqrt[3]{210}}{\sqrt[3]{1680}}=\cfrac{\sqrt{A}}{\sqrt{856}}](/tpl/images/0255/1627/7bc89.png)
![\dfrac{\sqrt{A}}{\sqrt{A'}}=\dfrac{\sqrt[3]{V}}{\sqrt[3]{V'}}](/tpl/images/0255/1627/b17ec.png)
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The volumes of two similar solids are 210 m3 and 1,680 m3. the surface area of the larger solid is 8...
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