Single equation: if sin b = -12/13, π< -b< 3π/2 what is the answer for sin 2b or sin b/2

Sin2B = 2sinBCosB (double angle formula)

sin(B/2) = 1/2 - 1/2 Cos(B)

Pi to 3pi/2 -> 3rd quadrant

cosB-> negative , sinB negative

CosB = -5/13

sin2B = 2 * -5/13 * -12/13 = 120/169

sinB/2 = 1/2 - 1/2 * * -5/13 = 9/13

a - base

b - exponent

so,

the base is 8the exponent is 3the exponent tells you to multiply 8 together three timesthe expanded form is 8*8*8