20pts
what is the distance between (7, 3, 4) and (5, 2, 9)?
really need !

To find the distance between two 3d points, square the difference of the x, y, and z points. Then, sum them and take the square root.
Distance=√(x2−x1)^2+(y2−y1)^2+(z2−z1)^2

Replace x^1,x^2,y^1,y^2,z^1, and z^2 with the corresponding values.
Distance=√((5)−(7))^2+((2)−(2))^2+((9)−(4))^2

Simplify √((5)−(7))^2+((2)−(2))^2+((9)−(4))^2
calculator

Distance= √29


The distance between (7,2,4) and (5,2,9) is √29.

√29≈5.38516481

Think of it as five or above give it a shove. change the 5 or above to the right to a zero and add one to the number on the left.

First subtract 10 from both side
y^2+6y-16=0
(y+8)(y-2)=0
-8 and 2