How many and what type of solution(s) does the equation have?
2w² + 50 = 20w
a. 2 irrational solutions
b. 1 rational solution
c. 2 rational solutions
d. 2 non-real solutions

Let's use the quadratic formula:

2w² - 20w + 50 = 0
a = 2  b = -20  c = 50

x = -b +-sq root(b^2 - 4*a*c) / 2*a
x = --20 +-sq root(400 -4*2*50) / 4
x = 20 +-sq root(400 -4*2*50) / 4
x = 20 +-sq root( 0) / 4
x = 20 / 4 =5
I'd say it has one rational solution. 
It does NOT have 2 solutions because the "plus / minus" section = 0.

First step is to get rid of the square root. remember that a square root is the same as raising to the (1/2) power. see below: multiply exponents per exponent rules to get: remember you subtract exponents from the denominator and add exponents in the numerator so: simplify further: so a is the correct choice. if you don't understand this google exponent rules and it will you understand. look at the image results.