Afactory produces 42,000 computer monitors per day. the manager of the factory claims that fewer than 660 defective computer monitors are produced each day. in a random sample of 240 computer monitors, there are 2 defective computer monitors. determine whether the manager’s claim is likely to be true. explain. no, the manager’s claim is not likely to be true. based on the data, you can predict that there are 665 defective computer monitors produced per day. yes, the manager’s claim is likely to be true. based on the data, you can predict that there are 350 defective computer monitors produced per day. yes, the manager’s claim is likely to be true. based on the data, you can predict that there are 355 defective computer monitors produced per day. no, the manager’s claim is not likely to be true. based on the data, you can predict that there are 670 defective computer monitors produced per day.

Based on the data, you can predict that there are 350 defective computer monitors produced per day.

Step-by-step explanation:

Given:

Number produced a day, n = 42,000

Defective monitors produced a day = < 600

From a random sample of 240 monitors, only 2 are defective.

For the average number of defective monitors, we have :

240/2 = 120

Which means in every 120 monitors produced, at least one must be defective.

Since 42,000 monitors are produced a day, the number of defective monitors produced a day will be:

42,000 / 120 = 350

350 defective monitors will be produced each day.

Based on the data, you can predict that there are 350 defective computer monitors produced per day.

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

e^-kt = n/n0 = 0.79  

-kt = ln 0.79  

t = - ln 0.79/0.0001  

= 2357 years

step-by-step explanation: