Find the number of real number solutions for the equation. x² + 26 = 0 ☺☻

a.) can not be determined from the graph
b.) 2
c.) 0
d.) 1

X^2+26=0
So x^2=-26
now x=squareroot(-26)
Since the value of x is squareroot(-26) which is not a real number and is a imaginary number so roots does not exist for this equation.
So option c 0 real roots is correct