Mathematics, 26.09.2019 01:30, DanielleSalv

Aneesha used linear combination to solve the system of equations shown. she did so by multiplying the first equation by 5 and the second equation by another number to eliminate the y-terms. what number did aneesha multiply the second equation by?
1. 6x + 2y = 28
7 x - 5y = - 4
clare used linear combination to solve the system of equations shown. she did so by multiplying the second equation by a certain number to eliminate the x-terms. what number did clare multiply the second equation by?
x - y = 5
0.5x + 0.1y = 8.5

Answers: 2

Show answers

Answers

In problem number 1, the answer is 2. because if Aneesha multiply the first equation with 5, 2y will become 10y and if she multiply the sencond equation with 2, 5y will become 10y and 10y from both equations cancel out each other.

in problem number 2, the answer is 2. it's the same logic as number 1. if you multiply 0.5x with 2, it will become 1 and cancel out with x from first equation.

answered: katherineedwards1105

1.
Multiply each equation by the value that makes the coefficients of y opposite.

5*(6x+2y)=5(28)
2*(7x−5y)=2(−4)

Simplify

30x+10y=140
14x−10y=−8

Add the two equations together to eliminate y from the system.

44x = 132
Simplify the equation and solve for x.

x = 3
Substitute the value found for x into one of the original equations, then solve for y.
y=5

(3,5)

Multiplied second equation by 2.

2.
x - y = 5
0.5x + 0.1y = 8.5

Multiply each term in the equation by 10.
10x−10y=50
5x+y=85

Multiply each equation by the value that makes the coefficients of x opposite.
−1*(10x−10y)=−1(50)
2*(5x+y)=2(85)

Simplify

−10x+10y=−50
10x+2y=170

Add the two equations together to eliminate x from the system.
12y = 120

Simplify the equation and solve for y.
y=10

Substitute the value found for y into one of the original equations, then solve for x.
x=15

(15,10)

Multiplied the second equation by 2.

answered: Guest

a) one student is chosen from classroom a, then a student is chosen from classroom b.

step-by-step explanation:

independent events are ones in which the probability of one event does not affect the probability of the second event.

one student is chosen from classroom a; this does not affect the chances of choosing a student from classroom b. this makes these independent events.

when one card is chosen from a standard deck and then set aside before a second card is chosen, the probability of the second card being chosen changes. this makes them dependent events.

when one student is chosen from classroom a and then a second student is chosen from classroom a, the probability of choosing the second student changes. this makes them dependent events.

when a letter is chosen from the alphabet and then a second letter is chosen, the probability of choosing the second letter changes. this makes them dependent events.

answered: Guest

-1 1/6. you dont subtract the denominators

step-by-step explanation: