Mathematics, 30.09.2019 01:50, pepehammu

Solve using substitution. (c& d)
2c+3d=1
-3c+d=15

Answers: 2

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Answers

Equation 2
-3c+d=15
d=15+3c

Substitute into eq 1
2c+3(15+3c)=1
2c+45+9c=1
11c=-44
c=-44/11

c=-4

Sub into eq 1

2(-4)+3d=1
-8+3d=1
3d=9
d=9/3

d=3

Verify:
2(-4)+3(3)=1
-8+9=1
1=1 -- True.

answered: Boayerik

2c + 3d = 1 ⇒ 2c + 3d = 1 ⇒ 2c + 3d = 1
-3c + d = 15 ⇒ 3(-3c + d) = 15 ⇒ -9c + 3d = 15
   -7c = 16
   -7c = 16
   -7 - 7
   c = -2 2/7
   2(2 2/7) + 3d = 1
       4 4/7 + 3d = 1
      -4 4/7    -4 4/7
   3d = -3 4/7
   3d = -3 4/7
      3 3
   d = -1 4/21
   (c, d) = (-2 2/7, -1 4/21)

answered: Guest

answer: 1722

step-by-step explanation:

given: the mass of saturn= $5.685\times10^{26}\ kgs$

the mass of mercury= $3.302\times10^{23}\ kgs$

the number of times the mass of saturn is greater than the mass of mercury

$=\frac{\text{mass of saturn}}{\text{mass of mercury}}\\=\frac{5.685\times10^{26}}{3.302\times10^{23}}\\\\=1.72168\times10^{26-23}{by using law of exponent}]\\=1.72168\times10^3=1721.68\approx1722$

hence, the mass of saturn is 1722 times greater than the mass of mercury.

answered: Guest

9 x 8 divided by (5-3)=36

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Solve using substitution. (c& d)
2c+3d=1
-3c+d=15...