The equation for the circle is:
x^2 + y^2 - 12x + 6y - 19 = 0
what is the center...
Mathematics, 03.02.2020 14:54, kaadenday3629
The equation for the circle is:
x^2 + y^2 - 12x + 6y - 19 = 0
what is the center of the circle?
a. (-6, 3)
b. (12, -6)
c. (6, -3)
d. (-12, 6)
Answers: 3
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