Mathematics, 14.10.2019 01:30, MallB7168

The equation for the circle is:
x^2+y^2−12x+6y−19=0x2+y2−12x+6y−19= 0 .
what is the center of the circle?

(-6, 3)
(12, -6)
(6, -3)

(-12, 6)

Answers: 3

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The equation for the circle is:
x^2+y^2−12x+6y−19=0x2+y2−12x+6y−19= 0 .
what is the cen...