Mathematics, 25.08.2019 06:20, gggggg47

What is the standard form for 25x²+4y²+50x-24y-39=0

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25x² + 4y² + 50x - 24y - 39 = 0
25x² + 50x + 4y² - 24y - 39 = 0
25x² + 50x - 39 = 0   4y² - 24y - 39 = 0
x = -b + √b² - 4ac y = -b + √b² - 4ac
      2a 2a
x = -50 + √(-50)² - 4(25)(-39)     y = -(-24) + √-(-24)² - 4(4)(-39)
   2(25) 2(4)
x = -50 + √2500 + 3900 y = 24 + √-576 + 624
   50 8
x = -50 + √6400 y = 24 + √48
      50    8
x = -50 + 80 y = 24 + √16 × 3
   50 8
x = -50 + 80 y = 24 + √16 √3
   50   8
x = -50 + 80    y = 24 + 4 √3
   50 8
x = -50 + 80                                        y = 24 + 4 √3
   50    8
x = -50 + 80   x = -50 - 80 y = 24 + 4 √3   y = 24 - 4 √3
      50 50 8     8
x = 30     x = -130     y = 28 √3     y = 20 √3
      50      50         8      8
x = 3     x = -13 y = 28 √3        y = 20 √3
      5     5    8     8
(x, y) = (3, 26 √3) (x, y) = (-13, 20 √3 )
        5    8 5 8

answered: wedderman6049

$25x^2+4y^2+50x-24y-39=0\\
25x^2+50x+25+4y^2-24y+36-100=0\\
(5x+5)^2+(2y-6)^2=100$

answered: Guest

x = -4

step-by-step explanation:

- 20 - 4(x + 3) = 4x

=> -20 - 4x - 12 = 4x

=> - 32 -4x = 4x

=> -32 = 4x + 4x

=> - 32 = 8x

=> -32/8 = x

=> -4 = x

answered: Guest

b and c

step-by-step explanation:

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