Select the statements that are true for the graph of y=(x+2)2+4 .

the vertex is (−2, 4) .

the graph has a maximum.

the graph has a minimum.

the vertex is (2, 4) .

I think you probably meant (x+2)^2+4 because the equation you have provided is not written in proper formatting and would actually be a straight line. However, if you meant for that second 2 to be an exponent, you now have a quadratic equation which would graph as  a parabola. Remember the basic formula is y=(x-h)^2 +k where (h,k) is your vertex. So you change the sign of the number in the parenthesis, but not the number outside the parenthesis when finding the vertex. If there is a negative number in front of your equation, then the parabola is flipped upside down so the vertex would be a maximum, but if it is positive, or has nothing in front of it, then the parabola sits up like a bowl so the vertex is a minimum.

Ibelieve that c. recording would work best.

Ithink the answer is c