Me!
a climatologist wants to determine the thickness of a glacier with a surface area of about 2 km². he selected 10 locations at random on the glacier and then measured the thickness of the glacier, in meters, at each location. 41, 38, 36, 29, 34, 44, 46, 43, 35, 40 what is the estimated median thickness of the entire glacier?

Median=39m

Step-by-step explanation:

It is given that the data set is in the form of the 10 locations on the glacier, so these are:

41, 38, 36, 29, 34, 44, 46, 43, 35, 40

In order to find the estimated median thickness of the entire glacier, we need to arrange the given data set in ascending order.Thus,

29, 34, 35, 36, 38, 40, 41, 43, 44, 46

Therefore, the median is:

Thus, the estimated median thickness of the entire glacier is 39m.

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v

ask the math teacher she or he would know lol.

step-by-step explanation: