Suppose the population of a town is 100,000 in 1999. the population increases at a rate of 4.5% every year. what will be the population of the town in 2005? round your answer to the nearest whole number.

130,226.

Step-by-step explanation:

We have been given that the population of a town is 100,000 in 1999. The population increases at a rate of 4.5% every year.

We will use exponential growth function to solve our given problem. We know that exponential function is in form , where,

= Final value,

a = Initial value,

b = For growth b is in form , where r represents rate in decimal form.  

Let us convert 4.5% into decimal form.

Upon substituting our given values in exponential growth formula, we will get:

, where x represents number of years after 1999.

To find population of town in 2005, we will substitute (2005-1999=6) in our function.

Therefore, the population of the town in 2005 will be 130,226.

amount of oatypop that contains the prize = 40%

amount   of oatypop which doesn't contain the prize = (100-40)=60%

probability that hannah will win a prize

    = s +f s +f f s+ff   f s+ff f f s+ infinity.where f= failure,s= success

=   or 60%

probability that hannah only has to buy 3 or less boxes before getting a prize= (s) and ( f s) and (ff s) and (f f f s)

        = = 87.04 %  

step-by-step explanation: