3pineapples, 2 cabbages and 6 bananas cost a total of $27.
2 pineapples, 3 cabbages and 4 bananas cost a total of $23.
4 pineapples, 1 cabbage and 8 bananas cost a total of $31.
find the costs of:
-one pineapple -one cabbage -one banana
* show your work step by step*

3p + 2c + 6b = 27
2p + 3c + 4b = 23
4p + 1c + 8b = 31

take any 2 equations and eliminate a variable

3p + 2c + 6b = 27
4p + 1c + 8b = 31multiply by -2

3p + 2c + 6b = 27
-8p - 2c - 16b = - 62 (result of multiplying by -2)
add
-5p - 10b = - 35

Now take one equation, and the other equation that u have not used already, and eliminate the same variable.

4p + 1c + 8b = 31multiply by -3
2p + 3c + 4b = 23

-12p - 3c - 24b = - 93 (result of multiplying by -3)
2p + 3c + 4b = 23
add
-10p - 20b = - 70

now take ur 2 equations that u eliminated the c in, and eliminate another variable

-5p - 10b = -35multiply by -2
-10p - 20b = -70

10p + 20b = 70 (result of multiplying by -2)
-10p - 20b = -70
add
0 = 0

when u get a result such as  0 = 0this means there is infinite solutions to this problem

Iwish i knew the answer but i don’t but someone will come and us