Timothy built a base for a circular tabletop. the base can support a tabletop with a radius of at least 6 inches, but not more than 23 inches.
what is the largest possible area of the tabletop that will fit on timothy’s table base? round the answer to the nearest whole square inch.

1,662  in²

Step-by-step explanation:

let the radius of the circular tabletop = r

The base can support a tabletop with a radius of at least 6 inches, but not more than 23 inches.

which mean r at least 6 in. and not more than 23 in.

∴ 6 ≤ r ≤ 23

Since the area of the circle = π * r²

So, the largest possible area of the tabletop will be for r = 23

So, the area = π * 23² = 1,661.9 in²

Round to the nearest whole square inch

So, The largest possible area of the tabletop is 1,662  in²

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3

i belive false if so your welcome if not well idk