What are the intercepts of the line 2x + 4y = 12?

if you're finding the x intercept, y is ALWAYS 0, so in this, you can just get rid of the -4y because you know that it's 0, so you're left with 2x=12 divide by 2 on both sides so you find x intercept is (6,0) on the graph 
the y works the same way, if you're looking for the y, you know that the x is zero, so you're left with -4y=12, divide by -4y on both sides and you end up with the y intercept being (0,-3) 

x int.= (6,0) 
y int.= (0,-3) 

by the way, when it's written like that, it's called standard form, so to find the intercepts on 2x=12+4y, you'd have to convert it into standard form (Ax=By=C) so you subtract 4y on both sides to make it 2x-4y=12, and then once you have it like that you can do the math to find the y and x intercepts.