L×W = 13×13
L×W = 169
Area of a square is expressed as A = L² where L is the length of one side of the square.
The rate of change of area will be expressed using chain rule as;
dA/dt = dA/dL * dL/dt where;
dL/dt is the rate at which the side length of the square is decreasing.
Given L = 7cm, dL/dt = 8cm/sec and dA/dL = 2L
dA/dL = 2(7)
dA/dL = 14cm
Substituting the given value into the chain rule expression above to get the rate of change of the area of the square, we will have;
dA/dt = dA/dL * dL/dt
dA/dt = 14cm * 8cm/sec
dA/dt = 112cm²/sec
Hence, the rate of change of the area of the square when the side length is 7 cm is 112cm²/sec
Remember, the formula of a square is . If I half x, is the new formula. Because the exponent is around the varialbe(x/2), both are squares. Therefore, the formula is .
Therefore, the new area is B: a quarter of the original.
To find the area it’s multiply the base and height: 44*44=1936cm^2
So your answer would be 1936cm^2
I hope this helps :)
2nd one in the first row is correct